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0.23=x^2+18.67x-27
We move all terms to the left:
0.23-(x^2+18.67x-27)=0
We get rid of parentheses
-x^2-18.67x+27+0.23=0
We add all the numbers together, and all the variables
-1x^2-18.67x+27.23=0
a = -1; b = -18.67; c = +27.23;
Δ = b2-4ac
Δ = -18.672-4·(-1)·27.23
Δ = 457.4889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18.67)-\sqrt{457.4889}}{2*-1}=\frac{18.67-\sqrt{457.4889}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18.67)+\sqrt{457.4889}}{2*-1}=\frac{18.67+\sqrt{457.4889}}{-2} $
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